##
Answer to Question nullterm-4

It recomputes strlen(*s*) each time around the loop.
Suppose that *s* has *n* characters. Then the loop goes
around *n* times. Each time, it spends time proportional
to *n* to compute strlen(*s*). So the total amount of time
is proportial to *n*^{2}. (If you buy *x* things
and each one costs *y* dollars then your total bill
is *xy* dollars.)
You could compute strlen(*s*) once and save it in a variable.
But it is not really necessary to compute strlen(*s*) even once.
A better approach is to end the loop when *s*[*i*] is a
null character.

int numNonblanks(const char* s)
{
int count = 0;
for(int i = 0; s[i] != '\0'; i++)
{
if(s[i] != ' ')
{
count++;
}
}
return count;
}